# Sample with MathJax contents

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$\frac{1}{3}$

Given the quadratic equation $a{x}^{2}+bx+c=0$ , one of the two roots is given by $$x=\frac{-b+\sqrt{{b}^{2}-4ac}}{2a}$$

Try this.

$\sqrt{\text{49}}$You should be able to see this inline equation: ${x}^{2}+{xy}^{2}+{xyz}^{2}=0$

The area of a circle is : $\pi {r}^{2}$

${x}^{2}+{x}^{3}+{x}^{4}+{x}^{5}$

**Web reference**

MathML specification